1 kg mole of oxygen `(O_(2))` has .......... electrons.

Options

A. `6.022xx10^(26)`
B. `16.022xx10^(26)`
C. `16.022xx10^(23)`
D. `16.022xx10^(20)`

Explanation

To find the number of electrons in 1 kg mole of oxygen (O₂), we can follow these steps:

### Step-by-Step Solution:

1. **Understand the concept of a mole**:
- A mole is a unit that represents a specific number of particles, which is Avogadro's number: \(6.022 \times 10^{23}\) particles.

2. **Determine the number of oxygen atoms in O₂**:
- Oxygen (O₂) is a diatomic molecule, meaning each molecule of oxygen contains 2 oxygen atoms.
- Each oxygen atom has 8 electrons. Therefore, in one O₂ molecule:
\[ \text{Electrons in O₂} = 2 \times 8 = 16 \text{ electrons} \]

3. **Calculate the number of moles in 1 kg mole**:
- 1 kg mole means 1000 moles. So:
\[ \text{Number of moles} = 1000 \text{ moles} \]

4. **Calculate the total number of O₂ molecules in 1 kg mole**:
- Since 1 mole contains \(6.022 \times 10^{23}\) molecules, then 1000 moles will contain:
\[ \text{Number of molecules} = 1000 \times 6.022 \times 10^{23} = 6.022 \times 10^{26} \text{ molecules} \]

5. **Calculate the total number of electrons in 1 kg mole of O₂**:
- Since each molecule of O₂ has 16 electrons, the total number of electrons in 1 kg mole of O₂ is:
\[ \text{Total electrons} = 16 \times 6.022 \times 10^{26} = 9.6352 \times 10^{27} \text{ electrons} \]

6. **Round off the answer**:
- We can express the final answer as:
\[ \text{Total electrons} \approx 9.6 \times 10^{27} \text{ electrons} \]

### Final Answer:
1 kg mole of oxygen (O₂) has approximately \(9.6 \times 10^{27}\) electrons.

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