The formula of phosphate of X is `XPO_(4)`. The formula of it's sulphate and chloride would be respectively

Options

A. `X_(2)(SO_(4))_(3).XCl_(3)`
B. `XSO_(4),XCl_(2)`
C. `X(SO_(4))_(2), X_(2)Cl`
D. `X_(2)SO_(4),XCl`

Explanation

To find the formulas for the sulfate and chloride of element X, we start with the information given about its phosphate, which is \( XPO_4 \).

### Step-by-Step Solution:

1. **Identify the Phosphate Ion**:
The phosphate ion is \( PO_4^{3-} \). This means that the valency of the phosphate ion is 3.

2. **Determine the Valency of X**:
Since the formula for the phosphate is \( XPO_4 \) and the phosphate has a valency of 3, we can conclude that the valency of element X must also be 3 to balance the charge. Therefore, \( X \) has a valency of 3.

3. **Find the Sulfate Ion**:
The sulfate ion is \( SO_4^{2-} \). The valency of sulfate is 2.

4. **Determine the Formula for Sulfate**:
To find the formula for the sulfate of X, we need to balance the valencies. Since the valency of X is 3 and the valency of sulfate is 2, we can use the cross-multiplication method:
- The formula will be \( X_2SO_4 \) because we need 2 sulfate ions to balance the 3 valency of X. Thus, the formula becomes \( X_2(SO_4)_{3} \).

5. **Find the Chloride Ion**:
The chloride ion is \( Cl^{-} \). The valency of chloride is 1.

6. **Determine the Formula for Chloride**:
Again, using cross-multiplication:
- Since the valency of X is 3 and the valency of chloride is 1, the formula for the chloride of X will be \( XCl_3 \).

### Final Formulas:
- The formula for the sulfate of X is \( X_2(SO_4)_{3} \).
- The formula for the chloride of X is \( XCl_3 \).

### Summary:
- Sulfate: \( X_2(SO_4)_{3} \)
- Chloride: \( XCl_3 \)