`HSO_(4)^(-) "with "HCOO^(-)`

Explanation

To solve the problem involving the reaction between \( \text{HSO}_4^{-} \) (hydrogen sulfate ion) and \( \text{HCOO}^{-} \) (formate ion), we can follow these steps:

### Step 1: Identify the Acid and Base
- **Acid**: An acid is a substance that donates protons (H⁺ ions). In this case, \( \text{HSO}_4^{-} \) can donate a proton.
- **Base**: A base is a substance that accepts protons. Here, \( \text{HCOO}^{-} \) can accept a proton.

### Step 2: Write the Reaction
- The reaction can be represented as:
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