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Which of the following does not give H^...

Which of the following does not give `H^(+)` ions in aqueous solution ?

A

`H_(2)CO_(3)`

B

`C_(2)H_(5)OH`

C

`CH_(3)COOH`

D

`H_(3)PO_(4)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine which of the following substances does not give \( H^+ \) ions in aqueous solution, we need to analyze each option provided. ### Step-by-Step Solution: 1. **Identify the Options**: The question presents several compounds. We need to evaluate each one to see if it produces \( H^+ \) ions when dissolved in water. 2. **Evaluate Each Compound**: - **Option 1**: (Not specified in the question but let's assume it is a strong acid like HCl) - Strong acids like HCl dissociate completely in water to produce \( H^+ \) ions. Therefore, this option does produce \( H^+ \) ions. - **Option 2**: \( C_2H_5OH \) (Ethanol) - Ethanol is a covalent compound and does not dissociate into ions in aqueous solution. Therefore, it does not produce \( H^+ \) ions. - **Option 3**: \( CH_3COOH \) (Acetic Acid) - Acetic acid is a weak acid that partially dissociates in water to produce \( H^+ \) ions. Therefore, it does produce \( H^+ \) ions. - **Option 4**: \( H_3PO_4 \) (Phosphoric Acid) - Phosphoric acid is a triprotic acid that dissociates in water to produce \( H^+ \) ions. Therefore, it does produce \( H^+ \) ions. 3. **Conclusion**: After evaluating all options, the only compound that does not produce \( H^+ \) ions in aqueous solution is **Option 2: Ethanol (\( C_2H_5OH \))**. ### Final Answer: **The compound that does not give \( H^+ \) ions in aqueous solution is \( C_2H_5OH \) (Ethanol).**

To determine which of the following substances does not give \( H^+ \) ions in aqueous solution, we need to analyze each option provided. ### Step-by-Step Solution: 1. **Identify the Options**: The question presents several compounds. We need to evaluate each one to see if it produces \( H^+ \) ions when dissolved in water. 2. **Evaluate Each Compound**: - **Option 1**: (Not specified in the question but let's assume it is a strong acid like HCl) ...
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