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CuO+XtoCuSO(4)+H(2)O.Here (X) is...

`CuO+XtoCuSO_(4)+H_(2)O`.Here (X) is

A

`CuSO_(4)`

B

HCl

C

`H_(2)SO_(4)`

D

`HNO_(3)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the equation \( \text{CuO} + X \rightarrow \text{CuSO}_4 + \text{H}_2\text{O} \), we need to identify what \( X \) is. Let's break it down step by step. ### Step 1: Identify the Reactants and Products - We have copper(II) oxide (\( \text{CuO} \)) as one of the reactants. - The products are copper(II) sulfate (\( \text{CuSO}_4 \)) and water (\( \text{H}_2\text{O} \)). ### Step 2: Determine the Nature of \( \text{CuO} \) - \( \text{CuO} \) is a metallic oxide, which is basic in nature. ### Step 3: Identify the Nature of \( X \) - Since \( \text{CuO} \) is basic, \( X \) must be an acid in order to react with the base to form salt and water. This is based on the neutralization reaction between an acid and a base. ### Step 4: Analyze Possible Acids - The possible candidates for \( X \) could be common acids like hydrochloric acid (\( \text{HCl} \)), sulfuric acid (\( \text{H}_2\text{SO}_4 \)), and nitric acid (\( \text{HNO}_3 \)). ### Step 5: Test Each Acid 1. **Hydrochloric Acid (\( \text{HCl} \))**: - Reaction: \( \text{CuO} + \text{HCl} \rightarrow \text{CuCl}_2 + \text{H}_2\text{O} \) - This produces copper(II) chloride, not copper(II) sulfate. So, \( \text{HCl} \) is not \( X \). 2. **Sulfuric Acid (\( \text{H}_2\text{SO}_4 \))**: - Reaction: \( \text{CuO} + \text{H}_2\text{SO}_4 \rightarrow \text{CuSO}_4 + \text{H}_2\text{O} \) - This produces copper(II) sulfate and water, which matches our required products. So, \( \text{H}_2\text{SO}_4 \) is a candidate for \( X \). 3. **Nitric Acid (\( \text{HNO}_3 \))**: - Reaction: \( \text{CuO} + \text{HNO}_3 \rightarrow \text{Cu(NO}_3)_2 + \text{H}_2\text{O} \) - This produces copper(II) nitrate, which is not the desired product. So, \( \text{HNO}_3 \) is not \( X \). ### Conclusion - The only acid that reacts with copper(II) oxide to produce copper(II) sulfate and water is sulfuric acid (\( \text{H}_2\text{SO}_4 \)). - Therefore, \( X = \text{H}_2\text{SO}_4 \). ### Final Answer \( X \) is \( \text{H}_2\text{SO}_4 \) (sulfuric acid). ---

To solve the equation \( \text{CuO} + X \rightarrow \text{CuSO}_4 + \text{H}_2\text{O} \), we need to identify what \( X \) is. Let's break it down step by step. ### Step 1: Identify the Reactants and Products - We have copper(II) oxide (\( \text{CuO} \)) as one of the reactants. - The products are copper(II) sulfate (\( \text{CuSO}_4 \)) and water (\( \text{H}_2\text{O} \)). ### Step 2: Determine the Nature of \( \text{CuO} \) - \( \text{CuO} \) is a metallic oxide, which is basic in nature. ...
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MTG IIT JEE FOUNDATION-ACIDS , BASES AND SALTS -Exercise (Multiple Choice Questions) LEVEL -2
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  2. When bitten by ant, the sting causes irritation due to the presence of

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  3. Acidity in the sugarcane juice is removed by adding

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  4. Which of the following salts on dissolving in water will give a solu...

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  5. In the given series of reaction . What are Y and Z respectively ? ...

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  6. What will be the pH value of a solution if salt of a strong acid a...

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  7. The equation between an acid and a base is XOH+HYtoXY+H(2)O Which...

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  8. P is produced by the action of chlorine on dry slaked lime . Q is ...

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  9. Two solutions A and B were found to have pH value of 6 and 8 respec...

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  10. Acetic acid was added to a solid 'X' kept in a test tube. A colourless...

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  11. A blue litmus paper was first dipped in dil .HCl and then in dil...

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  12. CuO+XtoCuSO(4)+H(2)O.Here (X) is

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  13. Which equilibrium can be described as an acid- base reaction using the...

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  14. One molecule of aluminium hydroxide will require how many molecule...

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  15. While preparing 20% aqueous sodium hydroxide solution in a beaker cer...

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  16. Breaking apart of the positive and negative ions of a compound in so...

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  17. Iron filings were added to a solution of copper sulphate .After 10 m...

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  18. 100 mL of a 0.1 M CH(3)COOH is titrated with 0.1 M NaOH solution .Th...

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  19. Calculate the pH of the solution in which 0.2 M NH(4)Cl and 0.1 M NH(3...

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  20. The pH of 0.05 M Ba(OH)(2) solution is

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