Write IUPAC names of the following compounds :
`CH_(3)-overset(Br)overset(|)CH-overset(Cl)overset(|)CH-CH_(3)`

Answer

To write the IUPAC name of the compound `CH₃-CH(Br)-CH(Cl)-CH₃`, we will follow a systematic approach. Here are the steps:

### Step 1: Identify the Parent Chain
The first step in IUPAC naming is to identify the longest continuous carbon chain in the compound. In this case, we have a chain of 4 carbon atoms.

### Step 2: Number the Carbon Atoms
Next, we need to number the carbon atoms in the chain. The numbering should be done in such a way that the substituents (Br and Cl) receive the lowest possible numbers.

- If we number from left to right:
- C1: CH₃
- C2: CH(Br)
- C3: CH(Cl)
- C4: CH₃

- If we number from right to left:
- C1: CH₃
- C2: CH(Cl)
- C3: CH(Br)
- C4: CH₃

In this case, numbering from left to right gives the substituents the lowest numbers (Br at C2 and Cl at C3).

### Step 3: Identify the Substituents
The substituents in this compound are:
- Bromo (Br) at position 2
- Chloro (Cl) at position 3

### Step 4: Combine the Information
Now we can combine the information to write the IUPAC name. The substituents are listed in alphabetical order, regardless of their position numbers.

- The name will start with the substituent that comes first alphabetically, which is Bromo (B) followed by Chloro (C).

### Step 5: Write the Final IUPAC Name
Putting it all together, the IUPAC name of the compound is:
**2-bromo-3-chlorobutane**

### Summary
The final IUPAC name for the compound `CH₃-CH(Br)-CH(Cl)-CH₃` is **2-bromo-3-chlorobutane**.

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