All the members of homologous series of alkynes have the general formula

Options

A. `C_(N)H_(2N)`
B. `C_(n)H_(2n+2)`
C. `C_(n)H_(2n-2)`
D. `C_(n)H_(2n-4)`

Explanation

To find the general formula for all the members of the homologous series of alkynes, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding Homologous Series**:
- A homologous series is a group of organic compounds that have the same functional group and similar chemical properties, but differ by a constant unit, typically -CH2.

2. **Identifying the Type of Hydrocarbons**:
- Alkynes are a type of hydrocarbons characterized by the presence of at least one triple bond between carbon atoms.

3. **Establishing the General Formula**:
- The general formula for alkynes can be derived based on the number of carbon atoms (n). The formula is given as CnH2n-2.
- Here, "n" represents the number of carbon atoms in the molecule.

4. **Calculating the First Few Members**:
- For n = 2 (the first member of alkynes), the formula gives:
- C2H(2*2-2) = C2H2 (which is Ethyne or Acetylene).
- For n = 3 (the second member):
- C3H(2*3-2) = C3H4 (which is Propyne).
- For n = 4 (the third member):
- C4H(2*4-2) = C4H6 (which is Butyne).

5. **Conclusion**:
- Therefore, the general formula for the homologous series of alkynes is CnH2n-2.

### Final Answer:
The general formula for all the members of the homologous series of alkynes is **CnH2n-2**.

---