When ethanoic acid is heated with `NaHCO_(3)` the gas evolved is

Options

A. `H_(2)`
B. `CO_(2)`
C. `CH_(4)`
D. `CO`

Explanation

To determine the gas evolved when ethanoic acid is heated with sodium bicarbonate (NaHCO₃), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactants in this reaction are ethanoic acid (CH₃COOH) and sodium bicarbonate (NaHCO₃).

2. **Understand the Reaction**:
- Ethanoic acid is a carboxylic acid. When it reacts with sodium bicarbonate, a neutralization reaction occurs. Sodium bicarbonate is a basic compound that reacts with acids to produce a salt, water, and carbon dioxide gas.

3. **Write the Reaction Equation**:
- The balanced chemical equation for the reaction can be written as:
\[ \text{CH}_3\text{COOH} + \text{NaHCO}_3 \rightarrow \text{CH}_3\text{COONa} + \text{CO}_2 + \text{H}_2\text{O} \]
- Here, CH₃COONa is sodium acetate, CO₂ is carbon dioxide, and H₂O is water.

4. **Identify the Gas Evolved**:
- From the reaction, we can see that carbon dioxide (CO₂) is one of the products formed when ethanoic acid reacts with sodium bicarbonate.

5. **Conclusion**:
- Therefore, the gas evolved when ethanoic acid is heated with sodium bicarbonate is carbon dioxide (CO₂).

### Final Answer:
The gas evolved is carbon dioxide (CO₂).