`C_(2)H_(4)` reacts with hydrogen in presence og Ni to give

Options

A. `CH_(4)`
B. `C_(2)H_(6)`
C. `HCOOH`
D. `HCHO`

Explanation

To solve the question regarding the reaction of \( C_2H_4 \) (ethylene) with hydrogen in the presence of nickel, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
The reactants in this reaction are \( C_2H_4 \) (ethylene) and hydrogen gas (\( H_2 \)).

2. **Understand the Reaction Type**:
This reaction is an example of a hydrogenation reaction. Hydrogenation is the process of adding hydrogen to an unsaturated hydrocarbon (which has double or triple bonds) to convert it into a saturated hydrocarbon (which only has single bonds).

3. **Recognize the Role of the Catalyst**:
Nickel (Ni) is used as a catalyst in this reaction. A catalyst speeds up the reaction without being consumed in the process.

4. **Draw the Structure of Ethylene**:
Ethylene (\( C_2H_4 \)) has the following structure:
\[ H_2C=CH_2 \]
This indicates that there is a double bond between the two carbon atoms.

5. **Add Hydrogen to the Double Bond**:
When hydrogen is added to the double bond in the presence of nickel, the double bond breaks, and each carbon atom forms a new bond with a hydrogen atom. This can be represented as:
\[ H_2C=CH_2 + H_2 \xrightarrow{Ni} H_3C-CH_3 \]

6. **Determine the Product**:
The product formed from this reaction is \( C_2H_6 \), which is known as ethane. The structure of ethane is:
\[ H_3C-CH_3 \]

7. **Write the Final Equation**:
The balanced chemical equation for the reaction can be written as:
\[ C_2H_4 + H_2 \xrightarrow{Ni} C_2H_6 \]

### Final Answer:
The product of the reaction between \( C_2H_4 \) and hydrogen in the presence of nickel is \( C_2H_6 \) (ethane).

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