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IUPAC name of the compound CH(2)=C(CH(...

IUPAC name of the compound
`CH_(2)=C(CH_(3))_(2)` is

A

1,1-dimethylprop-2-ene

B

2-methylprop-1-ene

C

2-ethyl-3,3-dimethylbutane

D

2,3-dimethylhexane

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The correct Answer is:
To determine the IUPAC name of the compound \( CH_2=C(CH_3)_2 \), we will follow the systematic steps for naming organic compounds according to IUPAC rules. ### Step-by-Step Solution: 1. **Identify the Parent Chain**: - The compound has a double bond (alkene) and branching. The longest continuous chain of carbon atoms that includes the double bond should be identified as the parent chain. - In this case, the longest chain consists of 3 carbon atoms (propene). 2. **Number the Carbon Atoms**: - Number the carbon atoms in the chain starting from the end nearest to the double bond to give the double bond the lowest possible number. - Here, we can number the chain as follows: - C1: \( CH_2 \) (first carbon) - C2: \( C \) (second carbon, part of the double bond) - C3: \( CH_3 \) (third carbon) - This gives us the numbering: 1 (C1) - 2 (C2) - 3 (C3). 3. **Identify Substituents**: - There are two methyl groups (\( CH_3 \)) attached to the second carbon (C2). - Therefore, we have two substituents on the parent chain. 4. **Assign Locants to Substituents**: - Since both methyl groups are on the second carbon, we denote this as 2,2-dimethyl. 5. **Combine the Name**: - The base name for a 3-carbon alkene is "propene". - Since we have a double bond starting at carbon 1, we denote it as "prop-1-ene". - Combine the substituents with the base name: 2,2-dimethylprop-1-ene. 6. **Final IUPAC Name**: - The final IUPAC name of the compound \( CH_2=C(CH_3)_2 \) is **2,2-dimethylprop-1-ene**. ### Summary: The IUPAC name of the compound \( CH_2=C(CH_3)_2 \) is **2,2-dimethylprop-1-ene**.

To determine the IUPAC name of the compound \( CH_2=C(CH_3)_2 \), we will follow the systematic steps for naming organic compounds according to IUPAC rules. ### Step-by-Step Solution: 1. **Identify the Parent Chain**: - The compound has a double bond (alkene) and branching. The longest continuous chain of carbon atoms that includes the double bond should be identified as the parent chain. - In this case, the longest chain consists of 3 carbon atoms (propene). ...
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MTG IIT JEE FOUNDATION-CARBON AND ITS COMPOUNDS -Exercise (Multiple Choice Questions) (LEVEL - 1)
  1. Alcohols can be prepared by hydration of

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  2. The reaction CH(4)+Cl(2)underset("light")overset("hv")rarrCH(3)Cl+HCl ...

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  3. When ethanoic acid is heated with NaHCO(3) the gas evolved is

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  4. Methane, ethane and propane are said to form a homologous series becau...

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  5. Which of the following belong to the same homologous series?

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  6. Ethane can be prepared by reaction of ethanol with

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  7. Which of the following is the functional group for carboxylic acid?

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  8. The structural formula of ethyl ethanoate is

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  9. Conversion of ethanol to ethanoic acid is a/an

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  10. In the reaction, CH(3)COONa+NaOHrarr the gas obtained is

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  11. Ethanol on complete oxidation gives

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  12. When the stopper of a bottle containing a colourless liquid was remove...

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  13. C(2)H(4) reacts with hydrogen in presence og Ni to give

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  14. Vegetable oils which are liquid at room temperature, can be converted ...

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  15. The following reaction is an example of CH(4)+2O(2)rarrCO(2)+2H(2)O+"h...

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  16. Complete the following reaction :

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  17. IUPAC name of (C(2)H(5))(2)CHCH(2)OH is

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  18. IUPAC name of the compound CH(3)underset(CH(3))underset(|)overset(CH...

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  19. IUPAC name of the compound CH(2)=C(CH(3))(2) is

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  20. In the presence of concentrated sulphuric acid, acetic acid reacts wit...

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