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A neutral organic compound A of molecula...

A neutral organic compound A of molecular formula `C_(2)H_(6)O`, on oxidation with potassium dichromate and sulphuric acid gives an acidic compound B. The compound A reacts with B on warming in presence of conc. `H_(2)SO_(4)` to give a sweet smelling substance C. C on heating with D gives back A.
Compound C in the above reaction is

A

an alcohol

B

an ester

C

a hydrocarbon

D

hydrogen

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The correct Answer is:
To solve the problem step by step, we need to analyze the information given in the question and the relationships between the compounds A, B, and C. ### Step 1: Identify Compound A - The molecular formula of compound A is \( C_2H_6O \). This formula suggests that compound A could be either an alcohol or an ether. - Given that it can be oxidized to form an acidic compound B, we can conclude that compound A is likely an alcohol. - The most likely candidate for \( C_2H_6O \) that fits this description is ethanol (\( CH_3CH_2OH \)). **Hint:** Look for functional groups in the molecular formula to determine the type of compound. ### Step 2: Oxidation of Compound A - When ethanol (A) is oxidized with potassium dichromate and sulfuric acid, it forms acetic acid (B), which is \( CH_3COOH \). - This confirms that compound B is acetic acid. **Hint:** Remember that primary alcohols oxidize to aldehydes and then to carboxylic acids. ### Step 3: Reaction of A with B - The reaction of ethanol (A) with acetic acid (B) in the presence of concentrated sulfuric acid leads to the formation of an ester, which is a sweet-smelling compound (C). - The reaction can be represented as: \[ CH_3CH_2OH + CH_3COOH \xrightarrow{H_2SO_4} CH_3COOCH_2CH_3 + H_2O \] - The compound formed (C) is ethyl acetate (\( CH_3COOCH_2CH_3 \)). **Hint:** Esters are often sweet-smelling compounds formed from the reaction of an alcohol and a carboxylic acid. ### Step 4: Heating Compound C with D - The question states that heating compound C with D gives back A. - When ethyl acetate (C) is heated with water (D) in a hydrolysis reaction, it can regenerate ethanol (A) and acetic acid (B). - This confirms that compound D is likely water. **Hint:** Hydrolysis reactions can regenerate the original reactants from esters. ### Final Conclusion - The sweet-smelling substance C formed in the reaction is ethyl acetate. **Final Answer:** Compound C is ethyl acetate (\( CH_3COOCH_2CH_3 \)).

To solve the problem step by step, we need to analyze the information given in the question and the relationships between the compounds A, B, and C. ### Step 1: Identify Compound A - The molecular formula of compound A is \( C_2H_6O \). This formula suggests that compound A could be either an alcohol or an ether. - Given that it can be oxidized to form an acidic compound B, we can conclude that compound A is likely an alcohol. - The most likely candidate for \( C_2H_6O \) that fits this description is ethanol (\( CH_3CH_2OH \)). **Hint:** Look for functional groups in the molecular formula to determine the type of compound. ...
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  13. PASSAGE-IV : A neutral organic compound A of molecular formula C(2)H(6...

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  14. PASSAGE-IV : A neutral organic compound A of molecular formula C(2)H(6...

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  15. A neutral organic compound A of molecular formula C(2)H(6)O, on oxidat...

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  16. PASSAGE-IV : A neutral organic compound A of molecular formula C(2)H(6...

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  17. PASSAGE-V : In the above sequences of reaction A is

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  18. PASSAGE-V : The compound B is

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  19. PASSAGE-V : In the sequence of reaction C is

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  20. PASSAGE-V : The reagent D is

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