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Explain the formation of (i) oxygen mole...

Explain the formation of (i) oxygen molecule and (ii) ethylene molecule with the help of Lewis dot structure.

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To explain the formation of (i) an oxygen molecule (O₂) and (ii) an ethylene molecule (C₂H₄) using Lewis dot structures, we will follow these steps: ### Formation of Oxygen Molecule (O₂) 1. **Identify the Molecular Formula**: The molecular formula for an oxygen molecule is O₂. 2. **Determine Valence Electrons**: Each oxygen atom has 6 valence electrons. Therefore, for two oxygen atoms, the total number of valence electrons is: \[ ...
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MTG IIT JEE FOUNDATION-CARBON AND ITS COMPOUNDS -Subjective Problems (Long Answer Type)
  1. Explain the formation of (i) oxygen molecule and (ii) ethylene molecul...

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  2. What are the main properties of covalent compounds with respect to mel...

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  3. Elements forming ionic compounds attain noble gas electronic configura...

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  4. Define the term 'isomers'.

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  5. Draw two possible isomers of the compound with molecular formula C(3)H...

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  6. Give the electron dot structures of the above two compounds.

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  7. Write the structural formulae for 2-methyl-2-butane

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  8. Write the structural formulae for 2-methylpropene.

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  9. Write the structural formulae for Methyl propyl ether

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  10. Write the structural formulae for 2,2-dimethyl propane

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  11. Write the structural formulae for 4,6-dimethyl hept-2-ene

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  12. Write IUPAC names of the following compounds : CH(3)CH(2)COOH

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  13. Write IUPAC names of the following compounds : CH(3)CHO

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  14. Write IUPAC names of the following compounds : CH(3)underset("I")und...

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  15. Write IUPAC names of the following compounds : CH(3)CH(2)CH(2)OH

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  16. Write IUPAC names of the following compounds : CH(3)underset("OH")un...

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  17. A hydrocarbon has three carbon atoms. Write down its molecular formula...

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  18. A hydrocarbon has three carbon atoms. Write down its molecular formula...

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  19. A hydrocarbon has three carbon atoms. Write down its molecular formula...

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  20. A hydrocarbon has three carbon atoms. Write down its molecular formula...

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