Write IUPAC names of the following compounds :
`CH_(3)underset("OH")underset(|)(C)HCH_(3)`

Answer

To write the IUPAC name for the compound \( CH_3CHOHCH_3 \), follow these steps:

### Step 1: Identify the Parent Chain
- Count the number of carbon atoms in the longest continuous chain. In this case, there are 3 carbon atoms.

### Step 2: Determine the Functional Group
- The functional group present in this compound is the hydroxyl group (-OH), which indicates that this is an alcohol.

### Step 3: Number the Carbon Atoms
- Number the carbon atoms in the parent chain. Start from the end closest to the functional group to give it the lowest possible number. Thus, the numbering will be:
- C1: \( CH_3 \)
- C2: \( CH(OH) \)
- C3: \( CH_3 \)

### Step 4: Assign the Position of the Functional Group
- The hydroxyl group (-OH) is attached to the second carbon atom (C2).

### Step 5: Write the Base Name
- With 3 carbon atoms, the base name is "propane".

### Step 6: Modify the Name for the Functional Group
- Since it is an alcohol, we replace the "e" in "propane" with "ol" to indicate the presence of the hydroxyl group. Thus, "propane" becomes "propanol".

### Step 7: Combine the Position and Base Name
- The final IUPAC name will be "propan-2-ol", indicating that the hydroxyl group is on the second carbon.

### Final Answer
The IUPAC name of the compound \( CH_3CHOHCH_3 \) is **propan-2-ol**.

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