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The number of molecules in 4.25 g of amm...

The number of molecules in 4.25 g of ammonia is approximately

A

`1xx10^(23)`

B

`1.5xx10^(23)`

C

`2.0xx10^(23)`

D

`2.5xx10^(23)`

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The correct Answer is:
To find the number of molecules in 4.25 g of ammonia (NH₃), we can follow these steps: ### Step 1: Determine the molar mass of ammonia (NH₃) The molar mass of ammonia can be calculated using the atomic masses of nitrogen (N) and hydrogen (H): - Atomic mass of nitrogen (N) = 14 g/mol - Atomic mass of hydrogen (H) = 1 g/mol Since ammonia has one nitrogen atom and three hydrogen atoms, the molar mass is: \[ \text{Molar mass of NH}_3 = 14 \, \text{g/mol} + (3 \times 1 \, \text{g/mol}) = 14 + 3 = 17 \, \text{g/mol} \] ### Step 2: Calculate the number of moles in 4.25 g of ammonia To find the number of moles, we use the formula: \[ \text{Number of moles} = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}} \] Substituting the values: \[ \text{Number of moles} = \frac{4.25 \, \text{g}}{17 \, \text{g/mol}} \] Calculating this gives: \[ \text{Number of moles} \approx 0.250 \, \text{moles} \] ### Step 3: Convert moles to molecules Using Avogadro's number, which is \( 6.022 \times 10^{23} \) molecules/mol, we can find the number of molecules: \[ \text{Number of molecules} = \text{Number of moles} \times \text{Avogadro's number} \] Substituting the values: \[ \text{Number of molecules} = 0.250 \, \text{moles} \times 6.022 \times 10^{23} \, \text{molecules/mol} \] Calculating this gives: \[ \text{Number of molecules} \approx 1.505 \times 10^{23} \, \text{molecules} \] ### Final Answer The number of molecules in 4.25 g of ammonia is approximately \( 1.505 \times 10^{23} \) molecules. ---

To find the number of molecules in 4.25 g of ammonia (NH₃), we can follow these steps: ### Step 1: Determine the molar mass of ammonia (NH₃) The molar mass of ammonia can be calculated using the atomic masses of nitrogen (N) and hydrogen (H): - Atomic mass of nitrogen (N) = 14 g/mol - Atomic mass of hydrogen (H) = 1 g/mol Since ammonia has one nitrogen atom and three hydrogen atoms, the molar mass is: ...
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MTG IIT JEE FOUNDATION-MOLE CONCEPT, STOICHIOMETRY AND BEHAVIOUR OF GASES -EXERCISE (MCQ)
  1. One mole of glucose contains moles of carbon.

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  2. One mole of CO(2) contains

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  3. The number of molecules in 4.25 g of ammonia is approximately

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  4. Number of mole of 1 m^(3) gas at NTP are:

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  5. An organic compound made of C, H and N contains 20% of nitrogen. Its m...

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  6. Percentage by weight of 'M' in MCl(3) is 20%. Atomic weight of that el...

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  7. 2.3xx10^(22) atoms of an element weigh 6.9 g. Atomic weight of that el...

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  8. Number of atoms present in 1.6 g of methane is

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  9. The vapour density of a gas is 11.2. The volume occupied by 11.2 g of ...

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  10. If 'M' is the molecular weight of a gas, what volume in L at STP would...

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  11. Number of moles of CaCO(3) which contain 1.5 moles of oxygen atoms is

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  12. The empirical formula of hydrogen peroxide is……………….

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  13. Which of the following is independent of temperature of a gas?

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  14. The absolute temperature of a gas

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  15. Which of the following graphs relates V and T?

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  16. The mass of carbon present in 0.5 mole of K(4)[Fe(CN)(6)] is -

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  17. How is pressure related to volume at constant temperature?

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  18. Equal volumes of different gases at any definite temperature and press...

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  19. The value of gas contant per degree per mol is approximately :

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  20. The total pressure of a mixture of two gases is

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