In a hydrocarbon the mass ratio of hydrogen to carbon is `1:3`. The empirical formula of the hydrocarbon is

Options

A. CH
B. `CH_(2)`
C. `CH_(4)`
D. `CH_(3)`

Answer

C

Explanation

`{:("Element",%,"At. wt.","Relative no. of atoms","Ratio"),("C",75,12,75//12=6.25,6.25//6.25=1),("H",25,1,25//1=25,25//6.25=4):}`
`therefore` Empirical formula = `CH_(4)`