If 0.56 g KOH is present in 100 mL of solution, then its normality will be

Options

A. 1 N
B. 0.1 N
C. 2 N
D. 0.2 N

Explanation

To find the normality of the KOH solution, we can follow these steps:

### Step 1: Understand the Concept of Normality
Normality (N) is defined as the number of gram equivalents of solute per liter of solution.

### Step 2: Calculate the Equivalent Weight of KOH
The equivalent weight of a substance can be calculated using the formula:
\[ \text{Equivalent Weight} = \frac{\text{Molar Mass}}{n} \]
where \( n \) is the number of replaceable ions or protons.

For KOH:
- Molar Mass of KOH = 56 g/mol
- Since KOH can release one OH⁻ ion, \( n = 1 \).

Thus, the equivalent weight of KOH is:
\[ \text{Equivalent Weight} = \frac{56}{1} = 56 \text{ g/equiv} \]

### Step 3: Calculate the Number of Gram Equivalents of KOH
The number of gram equivalents can be calculated using the formula:
\[ \text{Number of Gram Equivalents} = \frac{\text{Mass of Solute (g)}}{\text{Equivalent Weight (g/equiv)}} \]
Given that the mass of KOH is 0.56 g, we can substitute:
\[ \text{Number of Gram Equivalents} = \frac{0.56}{56} = 0.01 \text{ equiv} \]

### Step 4: Convert Volume from mL to L
The volume of the solution is given as 100 mL. To convert this to liters:
\[ \text{Volume (L)} = \frac{100 \text{ mL}}{1000} = 0.1 \text{ L} \]

### Step 5: Calculate Normality
Now we can calculate the normality using the formula:
\[ \text{Normality (N)} = \frac{\text{Number of Gram Equivalents}}{\text{Volume of Solution (L)}} \]
Substituting the values we have:
\[ \text{Normality (N)} = \frac{0.01 \text{ equiv}}{0.1 \text{ L}} = 0.1 \text{ N} \]

### Final Answer
The normality of the KOH solution is **0.1 N**.

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