The number of moles of NaCl in `250cm^(3)` of 0.50 M NaCl is

Options

A. 0.250 mol
B. 2 mol
C. 0.125 mol
D. 1 mol

Explanation

To find the number of moles of NaCl in 250 cm³ of a 0.50 M NaCl solution, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Definition of Molarity**:
Molarity (M) is defined as the number of moles of solute per liter of solution. The formula for molarity is:
\[ M = \frac{n}{V} \]
where \( n \) is the number of moles and \( V \) is the volume in liters.

2. **Convert Volume from cm³ to Liters**:
The volume given is 250 cm³. We need to convert this to liters.
\[ 1 \text{ cm}^3 = 1 \text{ ml} = 0.001 \text{ L} \]
Therefore,
\[ 250 \text{ cm}^3 = 250 \text{ ml} = \frac{250}{1000} = 0.25 \text{ L} \]

3. **Use the Molarity to Find the Number of Moles**:
We have the molarity (M) of the NaCl solution as 0.50 M. We can rearrange the molarity formula to find the number of moles \( n \):
\[ n = M \times V \]
Substituting the values we have:
\[ n = 0.50 \text{ mol/L} \times 0.25 \text{ L} \]

4. **Calculate the Number of Moles**:
Now, performing the multiplication:
\[ n = 0.50 \times 0.25 = 0.125 \text{ moles} \]

5. **Final Answer**:
Therefore, the number of moles of NaCl in 250 cm³ of 0.50 M NaCl solution is:
\[ n = 0.125 \text{ moles} \]