What type of bonds are formed in `N_2O_4` and what is the name of this compound?

Options

A. Covalent, dinitrogen tetraoxide
B. Covalent, nitrogen tetraoxide
C. Ionic, nitrogen oxide
D. Ionic, dinitrogen oxide

Explanation

To determine the type of bonds formed in \( N_2O_4 \) and the name of the compound, we can follow these steps:

### Step 1: Identify the elements and their electronic configurations
- Nitrogen (N) has an electronic configuration of \( 2,5 \).
- Oxygen (O) has an electronic configuration of \( 2,6 \).

### Step 2: Determine the number of electrons needed to complete the octet
- Nitrogen needs 3 more electrons to complete its octet.
- Oxygen needs 2 more electrons to complete its octet.

### Step 3: Analyze how the atoms can achieve a stable configuration
Since there are no metals to transfer electrons (which would create ionic bonds), the atoms will share electrons to achieve a full octet.

### Step 4: Draw the Lewis structure
In the Lewis structure for \( N_2O_4 \):
- Each nitrogen atom shares electrons with oxygen atoms.
- The structure shows that nitrogen and oxygen are bonded through shared pairs of electrons.

### Step 5: Identify the type of bond
Since the bonding involves the sharing of electrons between atoms, the bonds formed in \( N_2O_4 \) are **covalent bonds**.

### Step 6: Name the compound
The compound \( N_2O_4 \) consists of:
- 2 nitrogen (N) atoms
- 4 oxygen (O) atoms

The naming convention for covalent compounds involves using prefixes to denote the number of atoms. Thus, the name of \( N_2O_4 \) is **Dinitrogen Tetraoxide**.

### Final Answer
- The type of bonds formed in \( N_2O_4 \) is **covalent bonding**.
- The name of the compound is **Dinitrogen Tetraoxide**.

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