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Equilibrium constant for the reaction, ...

Equilibrium constant for the reaction,
`H_2O_((g)) + CO_((g)) to H_(2(g)) + CO_(2(g))` is 81. If the velocity constant of the forward reaction is `162 L mol^(-1)s^(-1)`, what is the velocity constant (in `L mol^(-1) s^(-1)`) for the backward reaction?

A

`13122 `

B

`2`

C

`261 `

D

`243`

Text Solution

Verified by Experts

The correct Answer is:
B
Since `K_c = (k_f)/(k_b)`
or `k_b = (k_f)/(K_c) = (162 L mol^(-1)s^(-1))/(81) = 2 L mol^(-1)s^(-1)`
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