In a chemical equilibrium, the rate constant for the backward reaction is `7.5xx10^(-4)` and the equilibrium constant is `1.5` the rate constant for the forward reaction is:

Options

A. `5 xx 10^(-4)`
B. `2 xx 10^(-3)`
C. `1.125 xx 10^(-3)`
D. `9.0 xx 10^(-4)`

Answer

C

Explanation

`K_c = k_f//k_b, 1.5 = k_f//(75 xx 10^(-4))`
or `k_f = 1.125 xx 10^(-3)`