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A sample of HI(g) is placed in flask at ...

A sample of `HI(g)` is placed in flask at a pressure of `0.2 atm`. At equilibrium. The partial pressure of `HI(g)` is `0.04 atm`. What is `K_(p)` for the given equilibrium?
`2HI(g) hArr H_(2)(g)+I_(2)(g)`

Text Solution

Verified by Experts

The correct Answer is:
4
`{:(,2HI_(g) , `therefore K_p = (p_(H_2) xx p_(I_2))/(p_(HI)^2) = (0.08 xx 0.08)/((0.04)^2) = 4`
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