A carboxylic acide `C_(2)H_(4)O_(2)` reacts with an alcohol in the presence of `H_(2)SO_(4)` to form a compound 'X'. The alcohol on oxidation with alkaline `KMnO_4` following by acidification gives the same caboxylic acid, `C_(2)H_(4)O_(2)`. Write the name and structure of
Alcohol.

Explanation

To solve the problem, we need to identify the alcohol that reacts with the carboxylic acid \( C_2H_4O_2 \) (which is ethanoic acid) to form a compound 'X'. Additionally, we know that the alcohol can be oxidized to yield the same carboxylic acid.

### Step-by-Step Solution:

1. **Identify the Carboxylic Acid**:
- The given carboxylic acid has the formula \( C_2H_4O_2 \).
- This corresponds to ethanoic acid (acetic acid), which has the structure:
\[
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