Copper(II) oxide reacts with ammonia to give copper, water and nitrogen.
`CuO_((s)) +NH_(3(g)) to xCu_((s))+yH_(2)O_((l)) +zN_(2(g))`
The value of (x + y + z) is

Explanation

To solve the reaction of Copper(II) oxide with ammonia, we start by writing the unbalanced chemical equation:

\[ \text{CuO}_{(s)} + \text{NH}_3_{(g)} \rightarrow x \text{Cu}_{(s)} + y \text{H}_2\text{O}_{(l)} + z \text{N}_2_{(g)} \]

### Step 1: Identify the Reactants and Products
- Reactants: Copper(II) oxide (CuO) and ammonia (NH₃).
- Products: Copper (Cu), water (H₂O), and nitrogen gas (N₂).

### Step 2: Write the Unbalanced Equation
The unbalanced equation is:
\[ \text{CuO} + \text{NH}_3 \rightarrow \text{Cu} + \text{H}_2\text{O} + \text{N}_2 \]

### Step 3: Balance the Nitrogen Atoms
In the products, we have nitrogen in the form of N₂. Since there are 2 nitrogen atoms in N₂, we need to balance it by placing a coefficient of 2 in front of NH₃:
\[ \text{CuO} + 2 \text{NH}_3 \rightarrow \text{Cu} + \text{H}_2\text{O} + \text{N}_2 \]

### Step 4: Balance the Hydrogen Atoms
From the 2 NH₃, we have 6 hydrogen atoms (2 NH₃ gives 2 × 3 = 6 H). To balance the hydrogen, we need 3 water molecules (since each water molecule has 2 hydrogen atoms):
\[ \text{CuO} + 2 \text{NH}_3 \rightarrow \text{Cu} + 3 \text{H}_2\text{O} + \text{N}_2 \]

### Step 5: Balance the Oxygen Atoms
Now, we have 3 oxygen atoms from 3 H₂O and 1 from CuO, which gives a total of 4 oxygen atoms on the product side. We need to ensure that the left side also has 4 oxygen atoms. Since we have 1 CuO, we need to balance it with 3 CuO:
\[ 3 \text{CuO} + 2 \text{NH}_3 \rightarrow 3 \text{Cu} + 3 \text{H}_2\text{O} + \text{N}_2 \]

### Step 6: Final Balanced Equation
The final balanced equation is:
\[ 3 \text{CuO} + 2 \text{NH}_3 \rightarrow 3 \text{Cu} + 3 \text{H}_2\text{O} + \text{N}_2 \]

### Step 7: Identify Values of x, y, and z
From the balanced equation:
- \( x = 3 \) (moles of Cu)
- \( y = 3 \) (moles of H₂O)
- \( z = 1 \) (moles of N₂)

### Step 8: Calculate \( x + y + z \)
Now, we can calculate:
\[ x + y + z = 3 + 3 + 1 = 7 \]

### Final Answer
The value of \( x + y + z \) is **7**.

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