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If both 'a' and 'b' are rational numbers...

If both 'a' and 'b' are rational numbers, then 'a' and 'b' from `(3-sqrt(5))/(3+2sqrt(5))=asqrt(5)-b` , respectively are

A

`(9)/(11),(19)/(11)`

B

`(19)/(11),(9)/(11)`

C

`(2)/(11),(8)/(11)`

D

`(10)/(11),(21)/(11)`

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The correct Answer is:
To solve the equation \(\frac{3 - \sqrt{5}}{3 + 2\sqrt{5}} = a\sqrt{5} - b\), where \(a\) and \(b\) are rational numbers, we will follow these steps: ### Step 1: Rationalize the Denominator To simplify the left-hand side, we will multiply the numerator and the denominator by the conjugate of the denominator, which is \(3 - 2\sqrt{5}\). \[ \frac{3 - \sqrt{5}}{3 + 2\sqrt{5}} \cdot \frac{3 - 2\sqrt{5}}{3 - 2\sqrt{5}} = \frac{(3 - \sqrt{5})(3 - 2\sqrt{5})}{(3 + 2\sqrt{5})(3 - 2\sqrt{5})} \] ### Step 2: Simplify the Denominator Now, we simplify the denominator using the difference of squares: \[ (3 + 2\sqrt{5})(3 - 2\sqrt{5}) = 3^2 - (2\sqrt{5})^2 = 9 - 20 = -11 \] ### Step 3: Expand the Numerator Next, we expand the numerator: \[ (3 - \sqrt{5})(3 - 2\sqrt{5}) = 3 \cdot 3 - 3 \cdot 2\sqrt{5} - \sqrt{5} \cdot 3 + \sqrt{5} \cdot 2\sqrt{5} \] \[ = 9 - 6\sqrt{5} - 3\sqrt{5} + 2 \cdot 5 = 9 - 9\sqrt{5} + 10 = 19 - 9\sqrt{5} \] ### Step 4: Combine the Results Now, we can combine the results from the numerator and denominator: \[ \frac{19 - 9\sqrt{5}}{-11} = \frac{-19 + 9\sqrt{5}}{11} = -\frac{19}{11} + \frac{9}{11}\sqrt{5} \] ### Step 5: Rearranging the Expression We can rearrange this expression to match the form \(a\sqrt{5} - b\): \[ \frac{9}{11}\sqrt{5} - \frac{19}{11} \] ### Step 6: Identify \(a\) and \(b\) From the expression \(\frac{9}{11}\sqrt{5} - \frac{19}{11}\), we can identify: \[ a = \frac{9}{11}, \quad b = \frac{19}{11} \] ### Conclusion Thus, the values of \(a\) and \(b\) are: \[ a = \frac{9}{11}, \quad b = \frac{19}{11} \]
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