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Find the value of (4)/((216)^(-2//3))-(1...

Find the value of `(4)/((216)^(-2//3))-(1)/((256)^(-3//4))`

A

`144`

B

`64`

C

`80`

D

`36`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the expression \( \frac{4}{(216)^{-\frac{2}{3}}} - \frac{1}{(256)^{-\frac{3}{4}}} \), we will follow these steps: ### Step 1: Simplify the negative exponents First, we rewrite the terms with negative exponents as follows: \[ \frac{4}{(216)^{-\frac{2}{3}}} = 4 \cdot (216)^{\frac{2}{3}} \] \[ \frac{1}{(256)^{-\frac{3}{4}}} = (256)^{\frac{3}{4}} \] So, we can rewrite the expression as: \[ 4 \cdot (216)^{\frac{2}{3}} - (256)^{\frac{3}{4}} \] ### Step 2: Prime factorization Next, we need to find the prime factorization of 216 and 256: - \( 216 = 6^3 \) (since \( 6 \times 6 \times 6 = 216 \)) - \( 256 = 4^4 \) (since \( 4 \times 4 \times 4 \times 4 = 256 \)) ### Step 3: Substitute the factorizations Now we substitute these factorizations back into the expression: \[ 4 \cdot (6^3)^{\frac{2}{3}} - (4^4)^{\frac{3}{4}} \] ### Step 4: Simplify the powers Using the power of a power property \((a^m)^n = a^{m \cdot n}\): \[ (6^3)^{\frac{2}{3}} = 6^{3 \cdot \frac{2}{3}} = 6^2 \] \[ (4^4)^{\frac{3}{4}} = 4^{4 \cdot \frac{3}{4}} = 4^3 \] So our expression now looks like: \[ 4 \cdot 6^2 - 4^3 \] ### Step 5: Calculate the powers Now we calculate \(6^2\) and \(4^3\): \[ 6^2 = 36 \] \[ 4^3 = 64 \] ### Step 6: Substitute and simplify Substituting these values back into the expression gives: \[ 4 \cdot 36 - 64 \] Calculating \(4 \cdot 36\): \[ 4 \cdot 36 = 144 \] Thus, we have: \[ 144 - 64 \] ### Step 7: Final calculation Finally, we perform the subtraction: \[ 144 - 64 = 80 \] ### Final Answer The value of the expression is \(80\). ---
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