Find zeroes of the polynomials given below :
(i) `3x+pi`
(ii) `ly+m, l ne 0`

Answer

To find the zeroes of the given polynomials, we will follow these steps:

### (i) For the polynomial \(3x + \pi\):

1. **Set the polynomial equal to zero**:
\[ 3x + \pi = 0 \]

2. **Isolate \(x\)**:
- Subtract \(\pi\) from both sides:
\[ 3x = -\pi \]

3. **Solve for \(x\)**:
- Divide both sides by 3:
\[ x = -\frac{\pi}{3} \]

Thus, the zero of the polynomial \(3x + \pi\) is:
\[ x = -\frac{\pi}{3} \]

### (ii) For the polynomial \(ly + m\) (where \(l \neq 0\)):

1. **Set the polynomial equal to zero**:
\[ ly + m = 0 \]

2. **Isolate \(y\)**:
- Subtract \(m\) from both sides:
\[ ly = -m \]

3. **Solve for \(y\)**:
- Divide both sides by \(l\) (since \(l \neq 0\)):
\[ y = -\frac{m}{l} \]

Thus, the zero of the polynomial \(ly + m\) is:
\[ y = -\frac{m}{l} \]

### Summary of Zeroes:
- For \(3x + \pi\): \(x = -\frac{\pi}{3}\)
- For \(ly + m\): \(y = -\frac{m}{l}\)