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If the polynomial x^(3)+2x^(2)-alphax-12...

If the polynomial `x^(3)+2x^(2)-alphax-12` is divided by `(x-4)` the remainder is `52` . Find the value of `alpha` .

A

`11//2`

B

`-5`

C

`8`

D

`-8`

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AI Generated Solution

The correct Answer is:
To find the value of α in the polynomial \( P(x) = x^3 + 2x^2 - \alpha x - 12 \) given that the remainder when divided by \( x - 4 \) is 52, we can follow these steps: ### Step 1: Apply the Remainder Theorem According to the Remainder Theorem, when a polynomial \( P(x) \) is divided by \( x - c \), the remainder is \( P(c) \). In this case, since we are dividing by \( x - 4 \), we will evaluate \( P(4) \). ### Step 2: Substitute \( x = 4 \) into the polynomial We substitute \( x = 4 \) into the polynomial: \[ P(4) = 4^3 + 2(4^2) - \alpha(4) - 12 \] ### Step 3: Calculate \( P(4) \) Calculating each term: - \( 4^3 = 64 \) - \( 4^2 = 16 \), so \( 2(4^2) = 2 \times 16 = 32 \) Now substituting these values into the polynomial: \[ P(4) = 64 + 32 - 4\alpha - 12 \] ### Step 4: Simplify the expression Now, we simplify: \[ P(4) = 64 + 32 - 12 - 4\alpha = 84 - 4\alpha \] ### Step 5: Set the equation equal to the remainder We know from the problem statement that \( P(4) = 52 \). Therefore, we set up the equation: \[ 84 - 4\alpha = 52 \] ### Step 6: Solve for \( \alpha \) Now, we solve for \( \alpha \): 1. Subtract 84 from both sides: \[ -4\alpha = 52 - 84 \] \[ -4\alpha = -32 \] 2. Divide both sides by -4: \[ \alpha = \frac{-32}{-4} = 8 \] ### Conclusion Thus, the value of \( \alpha \) is \( 8 \).
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