Home
Class 9
MATHS
In figure AB=CD, anglePAC= angleQBD, Pro...

In figure `AB=CD, anglePAC= angleQBD`, Prove that `DeltaAPC~=DeltaBQD`

Promotional Banner

Topper's Solved these Questions

  • TRIANGLES

    MTG IIT JEE FOUNDATION|Exercise SOLVED EXAMPLES |14 Videos

  • TRIANGLES

    MTG IIT JEE FOUNDATION|Exercise NCERT SECTION (Exercise 7.1)|14 Videos

  • STATISTICS

    MTG IIT JEE FOUNDATION|Exercise Olympiad/HOTS Corner |20 Videos

Similar Questions

Explore conceptually related problems

In the given figure, AB = CD and AD = CB. Prove that DeltaABD~=DeltaCDB .

In the figure it is given that AB=CD and AD=BC. Prove that DeltaABC~=DeltaCDA .

In the given figure, Ab = CD and angleABC=angleDCB=90^(@) . Prove that AC = DB.

In the given figure , AB = CD , CE = BF and angle ACE = angle DBF . Prove that triangle ACE cong triangle DBF

In the adjoining figure, AB = CD and AB||CD prove that (i) DeltaAOB cong DeltaDOC (ii) AD and BC bisect each other at the point O.

In the given figure , AB = CD , CE = BF and angle ACE = = angle DBF . Prove that AE = DF

In the adjoining figure AB = CD and AB"||"CD prove that : (i) DeltaAOB cong DeltaDOG (ii) AD and BC bisect each other at point O.

In the figure AB||CD, angleABE=100 . Find angleCDE :

In the given figure triangleAOB ~ triangleDOC , prove that AB||CD.