AD is an altitude of an isosceles triangle ABC in which AB = AC. Show that

AD bisects BC

AD is an altitude of an isosceles triangle ABC in which AB = AC. Show that AD bisects angleA

AD is an altitude of an isosceles DeltaABC in which AB = AC. Show that (i) AD bisects BC, (ii) AD bisects angleA .

AD and BE are respectively altitudes of an isosceles triangle ABC with AC=BC . Prove that AE=BD

triangle ABC and triangle DBC are isosceles triangles on the same base BC. Prove that line AD bisects BC at right angles

Find the length of altitude AD of an isosceles Delta ABC in which AB=AC=2a units and BC=a units.

In the adjoining figure, ABC is an isosceles triangle in which AB = AC. Also, D is a point such that BD = CD. Prove that AD bisects /_ A and /_D

The incircle of an isosceles triangle ABC , with AB=AC , touches the sides AB , BC , CA at D,E and F respectively. Prove that E bisects BC .

If D any point on the BC of an isosceles triangle ABC then prove that AB gt AD and AC gt AD .

The area of an isosceles triangle ABC with AB = AC and altitude AD = 3 cm is 12 sq cm . What is its perimeter?

If D is a point of the base BC an isosceles triangle ABC such that AD is perpendicular to AC, then a=