In `DeltaABC`, if AD is the bisector of `angleA`, show that `AB gt BD and AC gt DC`.

In DeltaABC , if AD is the bisector of angleA, show that ABgtBD and ACgtDC .

In Figure,if AD is the bisector of LA, show that: AB>BD( ii) AC>CD

In DeltaABC, AB+BC gt

In DeltaABC, AD is the bisector of angleA . Write AB, BD and DC in descending order of their length.

In following figure if AD if the bisector of angleABC, then prove that AB gt BD

In the given figure, ACgtAB and AD is the bisector of angleA. show that angleADC gt angleADB .

In Figure,AC>AB and AD is the bisector of LA. Show that ADC>/_ADB

In DeltaABC,AD is the bisector of angleA . Then , (ar(DeltaABD))/(ar(DeltaACD))=

In a Delta ABC, AD is the bisector of angle A . (i) If AB=6.4 cm, AC=8 cm and BD=5.6 cm, find DC. (ii) If AB=10 cm, AC=14 cm and BC=6 cm , find BD and DC. (iii) If AB=5.6 cm, BD=3.2 cm, and BC=6 cm , find AC. (iv) If AB=5.6 cm, AC=4 cm, and DC 3 cm , find BC.

In DeltaABC, if D is any point on the side BC, show that (AB+BC+AC)gt 2AD.