AB and CD are respectively the smallest and largest sides of a quadrilateral ABCD. Show that `angleA gt angleC and angleB gt angleC`.

AB and CD are respec­tively the smallest and longest sides of a quadrilateral ABCD (see th e given figure). Show that angle A gt angle C and angle B gt angle D

In Figure,AB and CD are respectively the smallest and longest sides of a quadrily the ABCD .Show that /_A>/_C and /_B>/_D

In a quadrilateral ABCD, angleA + angleC = 180^(@) , then angleB + angleD is equal to

(OA)/(OC)=(OD)/(OB) . Prove that angleA= angleC and angleB= angleD .

In squareABCD, AB is the smallest and CD is the largest side. Prove that : (i) angleB gt angleD (ii) angleA gt angle C

ABCD is a quadrilateral in which AB||DC and AD = BC. Prove that angleA=angleB and angleC= angleD .

In a quadrilateral ABCD, show that (AB+BC+CD+DA)gt(AC+BD) .

Bisectors of angles A and D of a quadrilateral ABCD meet at P. Prove that angleAPD=(1)/(2)(angleB+angleC)

If bisectors of angleA and angleB of a quadrilateral ABCD intersect each other at P, of angleB and angleC at Q, of angleC and angleD at R and of angleD and angleA at S, then PQRS is a

In quadrilateral ABCD, AB "||" CD and AD= BC, prove that angleA=angleB.