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In the given figure, sid BC of Delta ABC...

In the given figure, sid BC of `Delta ABC` is biseted at D and O is any point AD.BO and CO produced meet AC and AB at E and F respetively, and AD is respectively, and AD is produced to X so that D is the midpoint of OX. Prove that `AO:AX=AF:AB` and show that `EF||BC`.

A

3AC

B

`(1)/(2)AC`

C

2AC

D

`(1)/(3)AC`

Text Solution

Verified by Experts

The correct Answer is:
D
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