Home
Class 9
MATHS
In Fig. 13.98, BE | AC. AD is any line f...

In Fig. 13.98, `BE _|_ AC. AD` is any line from A to `BC` intersecting `BE` in `H.P. O and R` are respectively the mid-points of `AH, AB and BC.` Prove that `anglePOR = 90^@.`

Promotional Banner

Topper's Solved these Questions

  • QUADRILATERALS

    MTG IIT JEE FOUNDATION|Exercise EXERCISE (Subjective Problems) (Short Answer Type)|5 Videos

  • QUADRILATERALS

    MTG IIT JEE FOUNDATION|Exercise EXERCISE (Subjective Problems) (Long Answer Type)|5 Videos

  • QUADRILATERALS

    MTG IIT JEE FOUNDATION|Exercise EXERCISE (Comprehension Type PASSAGE- III )|3 Videos

  • PROBABILITY

    MTG IIT JEE FOUNDATION|Exercise OLYMPIAD/HOTS CORNER|20 Videos

  • STATISTICS

    MTG IIT JEE FOUNDATION|Exercise Olympiad/HOTS Corner |20 Videos

Similar Questions

Explore conceptually related problems

In Fig.13.98,BE perp AC.AD is any line from A to BC intersecting BE in H.P.O and R are respectively the mid-points of AH,AB and BC. Prove that /_POR=90^(@).

in figure,M is the mid-point of AB and N is the mid-point of BC(1) if AB=BC, prove that AM=NC

in figure,M is the mid-point of AB and N is the mid-point of BC(1) if AB=BC, prove that AM=NC

In Figure,AC>AB and D is the point on AC such that AB=AD. Prove that BC>CD

If D, E, F are respectively the mid-points of AB, AC and BC respectively in a Delta ABC, " then " vec (BE) + vec(AF) =

A ABCD is a rhombus and P,Q,R,S are the mid-points of AB,BC,CD,DA respectively.Prove that o+PQRS is a rectangle.

In Delta ABC, AB = AC. A circle is drawn with diameter AB and it intersects BC at D. Prove that D is the midpoint of BC.

In ∆ABC, AD is the bisector of ∠A meeting BC at D, CF ⊥ AB and E is the mid-point of AC. Then median of the triangle is