ABCD is a quadrilateral. The straight line through C parallel to the diagonal DB intersects AB produced at E. Prove that the ar(quad. ABCD) = ar`(triangleADE)`.

In the figure, ABCD is a quadrilateral. A line DP drawn parallel to diagonal AC from point D, meet BC produced at P. Prove that: are of Delta ABP = " area of " square ABCD

In the adjoining figure, ABCD is a quadrilateral. A line through D, parallel to AC, meets BC produced in P . Prove that ar(triangleABP)=ar("qaud. ABCD") .

ABCD is a parallelogram . The circle passing through the vertices. A, B and C intersects CD (or CD produced) at E. Prove that AE=AD .

In the figure, ABCDE is a pentagon. A line through B parallel to AC meets DC produced at F. Show that ar( Delta AEDF) = ar( Delta ABCDE)

P is any point on the diagonal BD of the parallelogram ABCD. Prove that ar (triangleAPD) = ar (triangleCPD) .

P is the mid-point of the side CD of a parallelogram ABCD. A line through C parallel to PA intersects AB at Q and DA produced at R. Prove that DA = AR and CQ = QR.

ABCD is a parallelogram.The circle through A,B and C intersects CD produced at E, prove that AE=AD

ABCD is a parallelogram.The circle through A ,B and C intersect CD( produced if necessary) at E.Prove that AE=AD

ABCD is a trapezium with AB||DC. A line parallel to AC intersects AB at X and BC at Y. Prove that ar( Delta ADX) = ar( Delta ACY).