Parallelogram ABCD and rectangle ABEF are on the same base AB and have equal areas. Show that the perimeter of the parallelogram is greater than that of the rectangle.

Parallelogram A B C D and rectangle A B E F have the same base A B and also have equal areas. Show that the perimeter of the parallelogram is greater than that of the rectangle. GIVE : A ^(gm)A B C D and a rectangle A B E F with the same base A B and equal areas. TO PROVE : Perimeter of ^(gm)A B C D > P e r i m e t e rofr e c t a nge l ABEF i.e. A B+B C+C D+A D > A B+B E+E F+A F

In figure, if parallelogram ABCD and rectangle ABEM are of equal area, then

If perimeter of two parallelograms are equal, then their areas are also equal.

A parallelogram and a rectangle stand on the same base and on the same side of the base with the same height. If l_(1), l_(2) be the perimeters of the parallelogram and the rectangle respectively, then which one of the following is correct ?

Show that the bisectors of angles of a parallelogram form a rectangle.

If the diagonals of a parallelogram are equal, then show that it is a rectangle

If a triangle and a parallelogram are on the same base and between the same parallels, then prove that the area of the triangle is equal to half the area of the parallelogram.

Parallelograms on the same base and between the same parallel are equal in area.