AD is a median of triangle ABC. G is a mid point of AD. If area of triangle ABC is 16 sq. cm. Find the area of triangle GDC

From the diagram,AD is median of triangle ABC and E is the midpoint of AD final area of triangle AEB (1)/(4) area of triangle ABC.What do you observe?

The medians of a triangle ABC meet at G. If the area of the triangle be 120 sq cm, then the area of the triangle GBC is

The centroid of a triangle ABC is G. The area of triangle ABC is 60 cm^(2) . The area of triangle GBC is.

Two triangles ABC PQR are congruent. If the area of Delta ABC is 60 sq. cm, then area of DeltaPQR will be

Consider the following statements : 1. Let D be a point on the side BC of a triangle ABC: If area of triangle ABD = area of triangle ACD, then for all points O on AD, area of triangle ABO = area of triangle ACO. 2. If G is the point of concurrence of the medians of a triangle ABC, then area of triangle ABG = area of triangle BCO = area of triangle ACG. Which of the above statements is/are correct?

In triangle ABC, AD, BE and CF are the medians intersecting at point G and area of triangle ABC is 156 cm^(2) . What is the area (in cm^(2) ) of triangle FGE ?

In a triangle ABC,having AD is median and area of triangle ABD=120m^(2). Find area of triangle ABC.

The mid points of sides of a triangle ABC are (2,1),(3,-1) and (0,0) .The area of triangle ABC is

In Fig.3, the area of triangle ABC( in sq.units ) is :

The three medians AD, BE and CF of Delta ABC intersect at point G. If the area of DeltaABC is 60 sq.cm. then the area of the quadrilateral BDGF is :