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The perimeter of a right angled triangle...

The perimeter of a right angled triangle is 24 cm. If its hypotenuse is 10 cm then area of this triangle is

A

24 `cm^2`

B

10 `cm^2`

C

12 `cm^2`

D

48 `cm^2`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we need to find the area of a right-angled triangle given its perimeter and hypotenuse. Here’s how we can do it: ### Step 1: Understand the given information We are given: - Perimeter of the triangle (P) = 24 cm - Hypotenuse (h) = 10 cm ### Step 2: Set up the equation for the perimeter The perimeter of a triangle is the sum of all its sides. For a right-angled triangle, we can denote the two other sides as \( a \) and \( b \). Therefore, we can write the equation: \[ a + b + h = P \] Substituting the known values: \[ a + b + 10 = 24 \] ### Step 3: Simplify the equation From the equation above, we can isolate \( a + b \): \[ a + b = 24 - 10 \] \[ a + b = 14 \] ### Step 4: Use the Pythagorean theorem For a right-angled triangle, the Pythagorean theorem states: \[ h^2 = a^2 + b^2 \] Substituting the value of the hypotenuse: \[ 10^2 = a^2 + b^2 \] \[ 100 = a^2 + b^2 \] ### Step 5: Set up a system of equations Now we have two equations: 1. \( a + b = 14 \) (Equation 1) 2. \( a^2 + b^2 = 100 \) (Equation 2) ### Step 6: Express one variable in terms of the other From Equation 1, we can express \( b \) in terms of \( a \): \[ b = 14 - a \] ### Step 7: Substitute into the second equation Now substitute \( b \) into Equation 2: \[ a^2 + (14 - a)^2 = 100 \] ### Step 8: Expand and simplify Expanding the equation: \[ a^2 + (196 - 28a + a^2) = 100 \] Combine like terms: \[ 2a^2 - 28a + 196 = 100 \] Subtract 100 from both sides: \[ 2a^2 - 28a + 96 = 0 \] ### Step 9: Simplify the quadratic equation Dividing the entire equation by 2: \[ a^2 - 14a + 48 = 0 \] ### Step 10: Factor the quadratic equation Now, we can factor the quadratic: \[ (a - 6)(a - 8) = 0 \] So, \( a = 6 \) or \( a = 8 \). ### Step 11: Find the corresponding values of \( b \) If \( a = 6 \), then: \[ b = 14 - 6 = 8 \] If \( a = 8 \), then: \[ b = 14 - 8 = 6 \] Thus, the sides of the triangle are \( 6 \) cm and \( 8 \) cm. ### Step 12: Calculate the area of the triangle The area \( A \) of a right-angled triangle is given by: \[ A = \frac{1}{2} \times a \times b \] Substituting the values: \[ A = \frac{1}{2} \times 6 \times 8 = \frac{48}{2} = 24 \text{ cm}^2 \] ### Conclusion The area of the triangle is \( 24 \text{ cm}^2 \). ---
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