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Form a grouped frequency distribution from the following data by inclusive method taking 4 as the class size of class intervals.
31, 23, 19, 29, 22, 20, 16, 10, 13, 34, 38, 33, 28, 21, 15, 18, 36, 24, 18, 15, 12, 30, 27, 23, 20, 17, 14, 32, 26, 25, 18, 29, 24, 19, 16, 11, 22, 15, 17,10

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To form a grouped frequency distribution using the inclusive method with a class size of 4 from the given data, we will follow these steps: ### Step 1: Arrange the Data in Ascending Order First, we need to arrange the given data in ascending order. **Data:** 10, 10, 10, 11, 12, 13, 14, 15, 15, 15, 15, 16, 16, 17, 17, 18, 18, 18, 19, 19, 20, 20, 20, 21, 21, 22, 22, 22, 23, 23, 24, 24, 25, 26, 26, 27, 28, 29, 29, 30, 31, 32, 33, 34, 36, 38 ### Step 2: Determine the Class Intervals We will create class intervals of size 4. The smallest number in the data is 10, so we will start from 10. **Class Intervals:** - 10 - 13 - 14 - 17 - 18 - 21 - 22 - 25 - 26 - 29 - 30 - 33 - 34 - 37 - 38 - 41 ### Step 3: Tally the Frequencies Now, we will count how many data points fall into each class interval. 1. **10 - 13:** 10, 10, 10, 11, 12, 13 (6) 2. **14 - 17:** 14, 15, 15, 15, 15, 16, 16, 17, 17 (9) 3. **18 - 21:** 18, 18, 18, 19, 19, 20, 20, 20, 21, 21 (10) 4. **22 - 25:** 22, 22, 22, 23, 23, 24, 24, 25 (8) 5. **26 - 29:** 26, 26, 27, 28, 29, 29 (6) 6. **30 - 33:** 30, 31, 32, 33 (4) 7. **34 - 37:** 34 (1) 8. **38 - 41:** 38 (1) ### Step 4: Create the Frequency Distribution Table Now we will summarize the data in a frequency distribution table. | Class Interval | Tally Marks | Frequency | |----------------|-------------|-----------| | 10 - 13 | ||||| ||| | 6 | | 14 - 17 | ||||| |||| | 9 | | 18 - 21 | ||||| ||||| | 10 | | 22 - 25 | ||||| |||| | 8 | | 26 - 29 | ||||| || | 6 | | 30 - 33 | ||||| | 4 | | 34 - 37 | | | 1 | | 38 - 41 | | | 1 | ### Step 5: Verify the Total Frequency Finally, we will sum the frequencies to ensure they match the total number of data points. **Total Frequency:** 6 + 9 + 10 + 8 + 6 + 4 + 1 + 1 = 45
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From a grouped frequency distribution from the following data by inclusive method taking 4 as the magnitude of class intervals. 31,23,19,29,22,20,16,10,13,34, 38,33,28,21,15,18,36,24,18,15, 12,30,27,23,20,17,14,32,26,25 18,29,24,19,16,11,22,15,17,10

Form a grouped frequency distribution from the following data by inclusive method taking 4 as the magnitude of class intervals. 31,23,19,29,22,20,16,10,13,34 38,33,28,21,15,18,36,24,18,15 12,30,27,23,20,17,14,32,26,25 18,29,24,19,16,11,22,15,17,10

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Construct a frequency table for the following ages (in years) of 30 students using equal class intervals, one of them being 9-12 , where 12 is not included. 18, 12, 7, 6, 11, 15, 21, 9, 8, 13, 15, 17, 22, 19, 14, 21, 23, 8, 12, 17, 15, 6, 18, 23, 22, 16, 9, 21, 11, 16 .

Tabulate , the given data by taking Class intervals : 1-10 , 11- 20 , 21- 30 , 31- 40 Data : 9 , 10 , 8 , 6 , 7 , 4 , 3 , 2, 16 , 28 , 22 , 36 , 24 , 18 , 27 , 35 , 19 , 29 , 23 , 34.

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The mean deviation about the mean for the values 18, 20, 12, 14, 19, 22, 26, 16, 19, 24 is

Draw the frequency polygon for the following data by drawing a histogram: {:("Class Interval",f),(" "0-5,10),(" "5-10,20),(" "10-15,15),(" "15-20,30),(" "20-25,32),(" "25-30,44):}

For the following data of daily wages (in rupees0 received by 30 labourers in a certain factory, construct a grouped frequency distribution table by dividing the range into class intervals of equal width, each corresponding to 2 rupees, in such a way that the mid-value of the first class interval corresponds to 12 rupees. 14,16,16,14,22,13,15,24,12,23,14,20,17,21,22,18,18,19,20,17,16,15,11,12,21,20,17,18,19,23

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