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There are 50 numbers. Each number is sub...

There are 50 numbers. Each number is subtracted from 43 and the mean of the numbers so obtained is found to be 5. The mean of the given numbers is

A

38

B

39

C

48

D

49

Text Solution

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The correct Answer is:
To solve the problem step by step, we can follow these instructions: ### Step 1: Understand the Problem We have 50 numbers. Each number is subtracted from 43, and the mean of the resulting numbers is 5. We need to find the mean of the original numbers. ### Step 2: Set Up the Equation Let the original numbers be \( x_1, x_2, \ldots, x_{50} \). When each number is subtracted from 43, we get new numbers: \[ 43 - x_1, 43 - x_2, \ldots, 43 - x_{50} \] The mean of these new numbers is given as 5. ### Step 3: Write the Mean Formula The mean of the new numbers can be expressed as: \[ \text{Mean} = \frac{(43 - x_1) + (43 - x_2) + \ldots + (43 - x_{50})}{50} \] This simplifies to: \[ \text{Mean} = \frac{50 \times 43 - (x_1 + x_2 + \ldots + x_{50})}{50} \] ### Step 4: Substitute the Given Mean We know that the mean of the new numbers is 5, so we can set up the equation: \[ 5 = \frac{50 \times 43 - (x_1 + x_2 + \ldots + x_{50})}{50} \] ### Step 5: Multiply Both Sides by 50 To eliminate the denominator, multiply both sides by 50: \[ 250 = 50 \times 43 - (x_1 + x_2 + \ldots + x_{50}) \] ### Step 6: Calculate \(50 \times 43\) Calculate \(50 \times 43\): \[ 50 \times 43 = 2150 \] So, we can rewrite the equation as: \[ 250 = 2150 - (x_1 + x_2 + \ldots + x_{50}) \] ### Step 7: Rearrange the Equation Rearranging gives us: \[ x_1 + x_2 + \ldots + x_{50} = 2150 - 250 \] \[ x_1 + x_2 + \ldots + x_{50} = 1900 \] ### Step 8: Find the Mean of the Original Numbers Now, we can find the mean of the original numbers: \[ \text{Mean} = \frac{x_1 + x_2 + \ldots + x_{50}}{50} = \frac{1900}{50} \] Calculating this gives: \[ \text{Mean} = 38 \] ### Final Answer Thus, the mean of the given numbers is **38**. ---
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MTG IIT JEE FOUNDATION-STATISTICS-Exercise (Multiple Choice Question)
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  2. The mean of 53 observations is 36. Out of these observations, the mean...

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  3. There are 50 numbers. Each number is subtracted from 43 and the mean o...

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  4. The median of the numbers 9, 5, 7, 17, 13, 18, 13, 9, 5, 17, 13, 12, 1...

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  5. The median of the numbers 45, 34, 65, 48, 93, 54, 22, 86, 45, 87 is

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  6. Mode of the data 51, 14, 71, 15, 91, 2, 51, 19, 41, 51, 18, 15, 51 is

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  7. For drawing a frequency polygon of a continuous frequency distribution...

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  8. The marks obtained by 20 students of a class in a test (out of 50) are...

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  9. The class mark of the class 150 - 170 is

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  10. The mean of eight numbers is 40. If one number is excluded, their mean...

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  11. The median of the data arranged in ascending order 8, 9, 12, 18, (x + ...

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  12. The points scored by a kabaddi team in a series of matches are as foll...

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  13. The marks obtained by 12 students of a class in a test are 36, 27, 5, ...

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  14. Find the mean of the following distribution:

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  15. The class marks of a frequency distribution are 104, 114, 124, 134, 14...

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  16. Find the mean of the following marks of 20 students on a screening tes...

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  17. The maximum temperatures (in degree celcius) for a city in North India...

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  18. The mean of 100 observations is 50. If one of the observations which w...

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  19. The mean weight of 60 students of a class is 52.75 kg. If mean weight ...

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  20. Mean of 20 observations is 17. If observation 40 is replaced by 12, th...

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