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Let barx be the mean of x1,x2,.....x3 a...

Let `barx` be the mean of `x_1,x_2,.....x_3` and `bary` be the mean of `y_1,y_2,....,y_n`. If `barz` is the mean of `x_1,x_2,.....,x_n,y_1,y_2,....y_n`, then `barz`=

A

`(barx+bary)`

B

`1/2(barx+bary)`

C

`1/n(barx+bary)`

D

`1/(2n)(barx+bary)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the mean \( \bar{z} \) of the combined observations \( x_1, x_2, \ldots, x_n, y_1, y_2, \ldots, y_n \), we can follow these steps: ### Step 1: Understand the means of the two sets Let: - \( \bar{x} \) be the mean of the observations \( x_1, x_2, \ldots, x_n \) - \( \bar{y} \) be the mean of the observations \( y_1, y_2, \ldots, y_n \) ### Step 2: Express the means in terms of sums The mean \( \bar{x} \) can be expressed as: \[ \bar{x} = \frac{x_1 + x_2 + \ldots + x_n}{n} \] Multiplying both sides by \( n \), we get: \[ x_1 + x_2 + \ldots + x_n = n \bar{x} \] Similarly, the mean \( \bar{y} \) can be expressed as: \[ \bar{y} = \frac{y_1 + y_2 + \ldots + y_n}{n} \] Multiplying both sides by \( n \), we get: \[ y_1 + y_2 + \ldots + y_n = n \bar{y} \] ### Step 3: Combine the sums Now, we need to find the total sum of all observations: \[ \text{Total Sum} = (x_1 + x_2 + \ldots + x_n) + (y_1 + y_2 + \ldots + y_n) \] Substituting the expressions from Step 2: \[ \text{Total Sum} = n \bar{x} + n \bar{y} \] ### Step 4: Find the total number of observations The total number of observations is: \[ \text{Total Observations} = n + n = 2n \] ### Step 5: Calculate the mean \( \bar{z} \) Now, we can find the mean \( \bar{z} \): \[ \bar{z} = \frac{\text{Total Sum}}{\text{Total Observations}} = \frac{n \bar{x} + n \bar{y}}{2n} \] This simplifies to: \[ \bar{z} = \frac{\bar{x} + \bar{y}}{2} \] ### Final Result Thus, the mean \( \bar{z} \) is given by: \[ \bar{z} = \frac{\bar{x} + \bar{y}}{2} \] ---
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MTG IIT JEE FOUNDATION-STATISTICS-Exercise (Multiple Choice Question)
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