die is tossed once. What is the probability of getting a number 4?

Answer

To solve the problem of finding the probability of getting a number 4 when a die is tossed once, we can follow these steps:

### Step 1: Identify the Sample Space
When a die is tossed, the possible outcomes are the numbers on the faces of the die. A standard die has six faces, numbered from 1 to 6. Therefore, the sample space (S) is:
\[ S = \{1, 2, 3, 4, 5, 6\} \]

### Step 2: Count the Total Outcomes
The total number of outcomes when tossing a die is the number of elements in the sample space. Since there are 6 faces on the die, the total number of outcomes (N) is:
\[ N = 6 \]

### Step 3: Identify the Favorable Outcomes
Next, we need to determine how many outcomes are favorable to the event of getting a number 4. In this case, there is only one favorable outcome, which is the number 4 itself. Therefore, the number of favorable outcomes (F) is:
\[ F = 1 \]

### Step 4: Calculate the Probability
The probability (P) of an event is given by the formula:
\[ P(\text{event}) = \frac{\text{Number of Favorable Outcomes}}{\text{Total Number of Outcomes}} \]
Substituting the values we found:
\[ P(\text{getting a 4}) = \frac{F}{N} = \frac{1}{6} \]

### Final Answer
Thus, the probability of getting a number 4 when a die is tossed once is:
\[ P(\text{getting a 4}) = \frac{1}{6} \]

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