A bag contains 6 green, 5 red, 8 yellow and 3 blue marbles. If a single marble is chosen at random from the bag, what is the probability of getting
a green marble

Answer

To find the probability of drawing a green marble from the bag, we can follow these steps:

### Step 1: Determine the total number of marbles in the bag.
- We have the following marbles:
- Green: 6
- Red: 5
- Yellow: 8
- Blue: 3

**Total number of marbles = 6 (green) + 5 (red) + 8 (yellow) + 3 (blue) = 22 marbles.**

### Step 2: Identify the number of favorable outcomes.
- The favorable outcome in this case is drawing a green marble.
- The number of green marbles is 6.

### Step 3: Calculate the probability.
- The probability of an event is given by the formula:

\[ \text{Probability} = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} \]

- Here, the number of favorable outcomes (green marbles) is 6, and the total number of outcomes (total marbles) is 22.

\[ \text{Probability of getting a green marble} = \frac{6}{22} \]

### Step 4: Simplify the fraction.
- We can simplify \(\frac{6}{22}\) by dividing both the numerator and the denominator by their greatest common divisor (GCD), which is 2.

\[ \frac{6 \div 2}{22 \div 2} = \frac{3}{11} \]

### Final Answer:
The probability of getting a green marble is \(\frac{3}{11}\).

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