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In a cricket match, a batsman hits a bou...

In a cricket match, a batsman hits a boundary 16 times out of 30 balls he plays. Find the probability that he does not hit a boundary.

A

`7//15`

B

`8//15`

C

`2//15`

D

`12//15`

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AI Generated Solution

The correct Answer is:
To find the probability that the batsman does not hit a boundary, we can follow these steps: ### Step-by-Step Solution: 1. **Identify Total Balls Played**: The batsman played a total of 30 balls. 2. **Identify Balls with Boundaries**: The batsman hit a boundary 16 times. 3. **Calculate Balls without Boundaries**: To find the number of balls on which the batsman did not hit a boundary, subtract the number of boundaries from the total balls played: \[ \text{Balls without boundaries} = \text{Total balls} - \text{Balls with boundaries} = 30 - 16 = 14 \] 4. **Calculate Probability of Not Hitting a Boundary**: The probability of an event is given by the formula: \[ \text{Probability} = \frac{\text{Number of favorable outcomes}}{\text{Total outcomes}} \] Here, the number of favorable outcomes (balls without boundaries) is 14, and the total outcomes (total balls played) is 30. Thus, the probability is: \[ P(\text{Not hitting a boundary}) = \frac{14}{30} \] 5. **Simplify the Fraction**: To simplify \(\frac{14}{30}\), we can divide both the numerator and the denominator by their greatest common divisor (GCD), which is 2: \[ \frac{14 \div 2}{30 \div 2} = \frac{7}{15} \] 6. **Final Answer**: Therefore, the probability that the batsman does not hit a boundary is: \[ \frac{7}{15} \]
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