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Two coins are tossed simultaneously for ...

Two coins are tossed simultaneously for 360 times. The number of times '2 Tails' appeared was three times 'No Tail' appeared and number of times '1 Tail' appeared is double the number of times 'No Tail' appeared. Find the probability of getting 'Two tails'.

A

`1//2`

B

`1//3`

C

`1//4`

D

`1//5`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we can follow these instructions: ### Step 1: Define Variables Let: - \( x \) = Number of times 'No Tail' appeared. - Therefore, the number of times '2 Tails' appeared = \( 3x \) (as given in the problem). - The number of times '1 Tail' appeared = \( 2x \) (as given in the problem). ### Step 2: Set Up the Equation According to the problem, the total number of outcomes when tossing the coins is 360. Therefore, we can write the equation: \[ x + 2x + 3x = 360 \] ### Step 3: Simplify the Equation Combine the terms on the left side: \[ 6x = 360 \] ### Step 4: Solve for \( x \) Now, divide both sides by 6 to find \( x \): \[ x = \frac{360}{6} = 60 \] ### Step 5: Find the Number of Times Each Outcome Occurred Now that we have \( x \): - Number of times 'No Tail' appeared = \( x = 60 \) - Number of times '1 Tail' appeared = \( 2x = 2 \times 60 = 120 \) - Number of times '2 Tails' appeared = \( 3x = 3 \times 60 = 180 \) ### Step 6: Calculate the Probability of Getting 'Two Tails' The probability \( P \) of getting 'Two Tails' is given by the formula: \[ P(\text{Two Tails}) = \frac{\text{Number of times 'Two Tails' appeared}}{\text{Total outcomes}} = \frac{180}{360} \] ### Step 7: Simplify the Probability Now simplify the fraction: \[ P(\text{Two Tails}) = \frac{180}{360} = \frac{1}{2} \] ### Final Answer Thus, the probability of getting 'Two Tails' is \( \frac{1}{2} \). ---
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MTG IIT JEE FOUNDATION-PROBABILITY-EXERCISE (MULTIPLE CHOICE QUESTIONS)
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