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In a game, a woman wins 16 times out of ...

In a game, a woman wins 16 times out of 20 balls she p lays. Find the probability that she does not win the game.

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To find the probability that the woman does not win the game, we can follow these steps: ### Step 1: Identify the number of wins and total games played. The woman wins 16 times out of 20 balls played. ### Step 2: Calculate the probability of winning. The probability of winning (P(win)) can be calculated using the formula: \[ P(\text{win}) = \frac{\text{Number of wins}}{\text{Total games played}} \] Substituting the values: \[ P(\text{win}) = \frac{16}{20} \] ### Step 3: Simplify the probability of winning. To simplify \( \frac{16}{20} \): \[ P(\text{win}) = \frac{16 \div 4}{20 \div 4} = \frac{4}{5} \] ### Step 4: Calculate the probability of not winning. The probability of not winning (P(not win)) can be found using the relationship: \[ P(\text{not win}) = 1 - P(\text{win}) \] Substituting the value we found: \[ P(\text{not win}) = 1 - \frac{4}{5} \] ### Step 5: Simplify the probability of not winning. Calculating this gives: \[ P(\text{not win}) = \frac{5}{5} - \frac{4}{5} = \frac{1}{5} \] ### Final Answer: The probability that the woman does not win the game is \( \frac{1}{5} \). ---
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