A coin is tossed 500 times with the following frequencies : Head : 255, Tail : 245.
Then the sum of the probabilities of each event is

Answer

To solve the problem, we need to find the sum of the probabilities of getting heads and tails when a coin is tossed 500 times. The frequencies of heads and tails are given as 255 and 245, respectively.

### Step-by-Step Solution:

1. **Identify Total Outcomes**:
The total number of times the coin is tossed is given as 500.

2. **Calculate Probability of Heads (P(H))**:
The probability of getting heads can be calculated using the formula:
\[ P(H) = \frac{\text{Number of Heads}}{\text{Total Outcomes}} = \frac{255}{500} \]

3. **Calculate Probability of Tails (P(T))**:
Similarly, the probability of getting tails can be calculated as:
\[ P(T) = \frac{\text{Number of Tails}}{\text{Total Outcomes}} = \frac{245}{500} \]

4. **Sum of Probabilities**:
Now, we need to find the sum of the probabilities of heads and tails:
\[ P(H) + P(T) = \frac{255}{500} + \frac{245}{500} \]

5. **Combine the Fractions**:
Since both fractions have the same denominator, we can add the numerators:
\[ P(H) + P(T) = \frac{255 + 245}{500} = \frac{500}{500} \]

6. **Simplify the Result**:
Simplifying \(\frac{500}{500}\) gives us:
\[ P(H) + P(T) = 1 \]

### Final Answer:
The sum of the probabilities of each event (heads and tails) is **1**.