Find the sum of numerator and denominator of the probability of choosing a day from a week.

Answer

To solve the problem of finding the sum of the numerator and denominator of the probability of choosing a day from a week, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Sample Space**:
The sample space for choosing a day from a week consists of the days:
- Sunday
- Monday
- Tuesday
- Wednesday
- Thursday
- Friday
- Saturday

Thus, the total number of outcomes in the sample space is 7.

2. **Define the Event**:
Let E be the event of choosing any one specific day from the week. The favorable outcome for this event is choosing one specific day.

3. **Calculate the Probability**:
The probability \( P(E) \) of choosing a specific day from the week is given by the formula:
\[ P(E) = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} \]
Here, the number of favorable outcomes is 1 (since we are choosing one specific day), and the total number of outcomes is 7 (the total days in a week). Therefore:
\[ P(E) = \frac{1}{7} \]

4. **Identify the Numerator and Denominator**:
From the probability \( \frac{1}{7} \), we can identify:
- Numerator = 1
- Denominator = 7

5. **Calculate the Sum of Numerator and Denominator**:
Now, we need to find the sum of the numerator and the denominator:
\[ \text{Sum} = \text{Numerator} + \text{Denominator} = 1 + 7 = 8 \]

### Final Answer:
The sum of the numerator and denominator of the probability of choosing a day from a week is **8**.

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