If (2,0) is a solution of the linear equations 2x+3y=k, then find the value of k.

Answer

To find the value of \( k \) in the linear equation \( 2x + 3y = k \) given that \( (2, 0) \) is a solution, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the given solution**: The point \( (2, 0) \) indicates that \( x = 2 \) and \( y = 0 \).

2. **Substitute the values of \( x \) and \( y \) into the equation**: We will replace \( x \) and \( y \) in the equation \( 2x + 3y = k \) with the values we identified.
\[ 2(2) + 3(0) = k \]

3. **Calculate the left-hand side**:
- First, calculate \( 2(2) \):
\[ 2(2) = 4 \]
- Next, calculate \( 3(0) \):
\[ 3(0) = 0 \]
- Now, add the two results together:
\[ 4 + 0 = 4 \]

4. **Set the left-hand side equal to \( k \)**:
\[ k = 4 \]

5. **Conclusion**: The value of \( k \) is \( 4 \).

### Final Answer:
\[ k = 4 \]