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The perimeter of a rectangle is 200 cm a...

The perimeter of a rectangle is 200 cm and its breadth is 36 cm. Find the area of the rectangle.

A

`7200 cm^(2)`

B

`2304 cm^(2)`

C

`360 cm^(2)`

D

`18040 cm^(2)`

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The correct Answer is:
To solve the problem step by step, we will follow these steps: ### Step 1: Understand the formula for the perimeter of a rectangle. The perimeter \( P \) of a rectangle is given by the formula: \[ P = 2(L + B) \] where \( L \) is the length and \( B \) is the breadth. ### Step 2: Substitute the known values into the perimeter formula. We know the perimeter \( P \) is 200 cm and the breadth \( B \) is 36 cm. We can substitute these values into the formula: \[ 200 = 2(L + 36) \] ### Step 3: Simplify the equation to find the length. First, divide both sides of the equation by 2: \[ 100 = L + 36 \] Next, isolate \( L \) by subtracting 36 from both sides: \[ L = 100 - 36 \] \[ L = 64 \text{ cm} \] ### Step 4: Calculate the area of the rectangle. Now that we have both the length and the breadth, we can find the area \( A \) using the formula: \[ A = L \times B \] Substituting the values we found: \[ A = 64 \times 36 \] ### Step 5: Perform the multiplication to find the area. Calculating \( 64 \times 36 \): \[ A = 2304 \text{ cm}^2 \] ### Final Answer: The area of the rectangle is \( 2304 \text{ cm}^2 \). ---
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MTG IIT JEE FOUNDATION-MENSURATION-Exercise (Multiple Choice Questions) Level - I
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