Home
Class 6
MATHS
How many bricks whose length and breadth...

How many bricks whose length and breadth are 12 cm and 6 cm, respectively, will be needed to fit in a rectangular region that measures `90 cm xx 120 cm` ? 

A

200

B

150

C

250

D

100

Text Solution

AI Generated Solution

The correct Answer is:
To find out how many bricks are needed to fit in a rectangular region measuring 90 cm by 120 cm, we will follow these steps: ### Step 1: Calculate the area of one brick. The dimensions of one brick are given as: - Length = 12 cm - Breadth = 6 cm The area \( A \) of one brick can be calculated using the formula: \[ A = \text{Length} \times \text{Breadth} \] Substituting the values: \[ A = 12 \, \text{cm} \times 6 \, \text{cm} = 72 \, \text{cm}^2 \] ### Step 2: Calculate the area of the rectangular region. The dimensions of the rectangular region are given as: - Length = 90 cm - Breadth = 120 cm The area \( A_r \) of the rectangular region can be calculated using the same formula: \[ A_r = \text{Length} \times \text{Breadth} \] Substituting the values: \[ A_r = 90 \, \text{cm} \times 120 \, \text{cm} = 10800 \, \text{cm}^2 \] ### Step 3: Determine the number of bricks needed. Let \( n \) be the number of bricks needed. The total area covered by \( n \) bricks is equal to the area of the rectangular region. Therefore, we can set up the equation: \[ n \times \text{Area of one brick} = \text{Area of rectangular region} \] Substituting the areas we calculated: \[ n \times 72 \, \text{cm}^2 = 10800 \, \text{cm}^2 \] ### Step 4: Solve for \( n \). To find \( n \), we can rearrange the equation: \[ n = \frac{10800 \, \text{cm}^2}{72 \, \text{cm}^2} \] Calculating this gives: \[ n = 150 \] ### Conclusion: Therefore, the number of bricks needed to fit in the rectangular region is \( \boxed{150} \). ---
Promotional Banner

Topper's Solved these Questions

  • MENSURATION

    MTG IIT JEE FOUNDATION|Exercise Exercise (Match the following)|2 Videos
  • MENSURATION

    MTG IIT JEE FOUNDATION|Exercise Exercise (Assertion & Reason Type)|5 Videos
  • MENSURATION

    MTG IIT JEE FOUNDATION|Exercise Exercise (Multiple Choice Questions) Level - I|35 Videos
  • KNOWING OUR NUMBERS

    MTG IIT JEE FOUNDATION|Exercise Olympiad/HOTS Corner|20 Videos
  • PLAYING WITH NUMBERS

    MTG IIT JEE FOUNDATION|Exercise OLYMPIAD/HOTS CORNER |18 Videos

Similar Questions

Explore conceptually related problems

How many tiles whose length and breadth are 12cm and 5cm respectively will be needed to fit in a rectangular region whose length and breadth are respectively: (a) 100cm and 144cm(b)70cm and 36cm.

Find the area of a rectangle whose length and breadth are12cm and 4cm respectively

How many marble tiles of 12 cm xx 3 cm will be needed to fit in a rectangular region of length 90 cm and breadth 40 cm ?

The length and breadth of a rectangle are 12 cm and 5 cm respectively. Calculate its perimeter (in cm).

The length and breadth of a rectangular garden is 12 cm and 9 cm. What will be the area of the rectangular garden?

Find the perimeter of a rectangle whose length and breadth are 15.4 cm and 11.6 cm respectively.

The volume of the coboid, whose length, breadth and height are 10cm, 8 cm and 6cm respectively is :

The length and breadth of a rectangle are 12cm and 5cm respectively,then its diagonal is ...............cm.